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112n^2-567=0
a = 112; b = 0; c = -567;
Δ = b2-4ac
Δ = 02-4·112·(-567)
Δ = 254016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{254016}=504$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-504}{2*112}=\frac{-504}{224} =-2+1/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+504}{2*112}=\frac{504}{224} =2+1/4 $
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